A 10.0 mL of 0.121 M H₂SO₄ is neutralized by 17.1 mL of KOH solution. The molarity of the KOH solution is H₂SO₄(aq)+2KOH(aq)→K₂SO₄(aq)+2H₂O(h)
A) 0.207M.
B) 0.4141M.
C) 0.0708M.
D) 0.142M