Consider the cell described below at 299 K: Sn | Sn2+ (0.785 M) || Pb²⁺ (0.939 M) | Pb Given EoPb²⁺→Pb = -0.131 V, EoSn2+→Sn = -0.143 V. Calculate the cell potential after the reaction has operated long enough for the Sn2+ to have changed by 0.325 mol/L.
