Consider the integral ∫04x2+x−61dx There is a disconintultyin the interval of integration at a= . which requires splitting the integral into two Type 2 improper integrals: ∫011f(x)dx+∫04f(x)dx A. The integral converges because both ∫0af(x)dx and ∫a4f(x)dx converge, with ∫01f(x)dx= B. The integral diverges because ∫0af(x)dx=