Consider the integral ∫04​x2+x−61​dx There is a disconintultyin the interval of integration at a= . which requires splitting the integral into two Type 2 improper integrals: ∫011​f(x)dx+∫04​f(x)dx A. The integral converges because both ∫0a​f(x)dx and ∫a4​f(x)dx converge, with ∫01​f(x)dx= B. The integral diverges because ∫0a​f(x)dx=