Based off of the balanced chemical equation:
2Al+6HCl--->2AlCl3+3H2;
How many grams of H2 gas can be produced if 50.0 grams of Al react?
Step 1: Stiochiometric Ration:
=2moles of Al:6moles of HCl yeilds 2moles of AlCl3:3moles of H2 (1mole of Al and 3moles of HCl will yeild one mole of AlCl3 and 1.5 moles of H2)
Step 2: Determine Molar Ratio and Starting units
=Starting units: 50.0grams of Al
=Molar ratio: 3mols of H2/2mols of Al
Step 3: Construct Data Table (dimensional analysis) and Solve
(50.0grams Al)x(2molAl/53.96grams Al)x(3mols H2/2mols H2)x(6.05grams H2/3mols H2) =5.606 grams of H2 gas wil be produced if 50 grams of Al react.
Did I solve correctly? Is the answer of 5.606 grams of H2 gas correct?
