Explain why the interval of definition of the explicit solution y = 2(x) of the initial-value problem in example 2 is the open interval (-5, 5).
a) The function is discontinuous outside the interval (-5, 5).
b) The function is undefined at x = -5 and x = 5.
c) The function has vertical asymptotes at x = -5 and x = 5.
d) The function is defined only within the interval (-5, 5).
