Resolve the vector A = xi + 2yj + βk along and perpendicular to the line which makes an angle of 60 degrees with the x-axis.
A) A_parallel = 2i - √3j + βk, A_perpendicular = -i + √3j
B) A_parallel = -2i + √3j - βk, A_perpendicular = i - √3j
C) A_parallel = -2i + √3j - βk, A_perpendicular = i - √3j
D) A_parallel = 2i - √3j + βk, A_perpendicular = -i + √3j
