For the probability that the responsible doesn't miss a call between 2:00 and 6:00 in the morning, which approach is correct?
a) What is the probability that he doesn't miss a call
b) Assume he has to pay a fine of 5$ for each missed call. What is the expectation and the variance of the amount he has to pay as fine.
I'm thinking this is a Poisson problem
for the first part a) I tried subtracting 0 calls from 1
1−((e−16)∗(1610)/0!=0.99999991−((e−16)∗(1610)/0!=0.9999999
but the actual answer is 0.51341710.5134171
for b)