Assume you visit a popular tourist spot and read in the newspaper that in 4 out of every 9 restaurants checked, there were unsatisfactory health conditions found. Assuming you are planning to each out 14 times while you are on vacation, answer the following: How likely is it that you will eat at three restaurants with unsanitary conditions? Explain how you would compute the probability of eating in at least one restaurant with unsanitary conditions. Could you use the complement to solve this problem? Is this a binomial distribution? If it is a binomial distribution, does that mean that the likelihood of a success is always 50% since there are only two possible outcomes?
