A hydrocarbon, 'X' (C₃H₄) decolourises Br2/CCl₄ solution forming 'Y'. 'X' gave a red precipitate of a compound 'Z' with ammoniacal cuprous chloride.
X, Y, and Z respectively are:
A. CH₂=C=CH₂, CH₂Br−CBr₂−CH₂Br, CH₃−C≡C⁻Cu⁺
B. CH₃−C≡CH, CH₃−CBr₂−CHBr₂, CH₃−C≡C⁻Cu⁺
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C. CH₃−C≡CH, CH₃−CBr=CHBr, Cu⁺CH₂⁻−C≡CH
D. CH₂=C=CH₂, CH₂Br−CH=CHBr; CH₃−C≡C⁻Cu⁺
