EMF of the following cell is 0.634 volt at 298 K. ltbr> Pt∣Hg₂)(1atm)H⁺(aq)||KCl(1N)|Hg₂Cl₂(s)|Hg
Calculate pH of the anode compartment.
[Given: E°Cₗ⁻|Hg₂Cl₂|Hg = 0.28 V and 2.303Rt/F=0.059]