Question

Solve the following system of equations algebraically using linear combination and substitution:
x+y−3z=8
2x−3y+z=−6
3x+4y−2z=20
a) x=2,y=−3,z=−1
b) x=−1,y=2,z=3
c) x=3,y=−1,z=2
d) x=1,y=−2,z=−3