presleystevenss3710 presleystevenss3710 29-12-2023 Mathematics contestada In triangle ABC, show that the midsegment ED is parallel to BC and that ED = 1/2BC. a. ED || BC and ED = 1/2BC b. ED || AC and ED = 1/2AC c. ED || AB and ED = 1/2AB d. ED || BC and ED = BC
