From a table of integrals, we know that for ,≠0a,b≠0,
∫cos()=⋅cos()+sin()2+2+.∫eatcos(bt)dt=eat⋅acos(bt)+bsin(bt)a2+b2+C.
Use this antiderivative to compute the following improper integral:
∫[infinity]01cos(3)− = limT→[infinity]∫0[infinity]e1tcos(3t)e−stdt = limT→[infinity] if ≠1s≠1
or
∫[infinity]01cos(3)− = limT→[infinity]∫0[infinity]e1tcos(3t)e−stdt = limT→[infinity] if =1.s=1. help (formulas)
For which values of s do the limits above exist? In other words, what is the domain of the Laplace transform of 1cos(3)e1tcos(3t)?
help (inequalities)
Evaluate the existing limit to compute the Laplace transform of 1cos(3)e1tcos(3t) on the domain you determined in the previous part:
()=L{e^1t cos(3)}=
