Use the appropriate standard reduction potentials below to determine the equilibrium constant at 391 K for the following reaction under acidic conditions. 41" (aq) + Mn0,(s) +2Fe2+ (aq) --Mn?* (aq) + 2Fe2+ (aq) + 2H,001) Standard reduction potentials: Mnog(x) +44 (aq) +20 - Mn?" (aq) +H,0(1) E - 1.23 V Fe?+ (aq) + 6 Fe?" (ag) = 0.770 V
