Tarzan swings on a 30.0m long vine initially inclined at an angle of 37.0 degree with the vertical. What is his speed at the bottom of the swing Question: (a) if he start from rest? (b) If he pushes off with a speed of 4.00 m/s?Formula: This problem does not include the potential energy of the spring. So, you can exclude in solving for the delta Ug + delta Us + delta K = 0 for the conservative forceIn our class the nonconservative forces are: tension, push of a finger, friction, and etc. conservative forces are: spring and gravity (ONLY)PlEaSe: Provide a step - by - step procedures on how you get your answers. If you can provide a picture of Tarzan swinging that would be awesome. Thank you in advance. delta Ug + delta Us + delta K = Wnc for the nonconservative force delta Us from the formula given below.
