To proof that 7 to the power of n space end exponent minus space 1 space is space divisible space b y space 6 space for space all space positive space integer space n. We want to prove by mathematical induction. Which of the following is in induction step?
Answers:
When n = 1, the statement is true
7 to the power of n plus 1 end exponent minus 1 equals 7 left parenthesis 7 to the power of n minus 1 right parenthesis space space plus space 6
7 to the power of n minus 1 space equals space 7 left parenthesis 7 to the power of n minus 1 end exponent minus 1 right parenthesis plus 6
W h e n space n space equals space 2 comma space 7 squared minus 1 space equals space 48 space i s space d i v i s i b l e space b y space 6
Response Feedback:
Student shall know five proof skills. Direct proof, proof by contradiction, proof by cases, proof by contrapositive, and proof by mathematical indcution
