Questions: 1. What are our starting conditions at sea level (0 elevation) on Figure 2? °℃ Starting Temperature = 5 Water Capacity at that temperature (Table 1 on 1.3) = 10 Relative Humidity at start point (Figure 2) = That relative humidity then means actual content is = 20 Temp that actual content would saturate air (Table 1) = 25 (Note this last value is now our target for the following section) 50 g/kg % g/kg °℃ 2. The air at sea level is (SATURATED UNSATURATED) 3. The air will initially (WARM/COOL) as it rises over the windward side of the mountain. It changes temperature at the (WET / DRY) adiabatic lapse rate, which is °C per 100 meters. 4. The rising air will reach its dew point temperature (last line in question 1 meters and water vapor will above) at an elevation of begin to (CONDENSE / EVAPORATE). 5. From the altitude where condensation begins to occur, to the top of the mountain, the rising air will continue to expand and will (WARM/ COOL) at °C per 100 meters. the (WET / DRY) adiabatic lapse rate of 6. The temperature of the rising air at the summit of the mountain (elevation 5000 meters) will be °C. 7. When the air begins to descend on the leeward side of the mountain, it will be compressed and its temperature will (INCREASE / DECREASE). 8. Assume that the relative humidity of the air is below 100% during its entire descent to the plateau. The air will be (SATURATED / UNSATURATED) and will warm at the (WET/DRY) adiabatic lapse rate of about °C per 100 meters. 9. As the air descends and warms on the leeward side of the mountain, its relative humidity will (INCREASE / DECREASE) 10. The air's temperature when it reaches the plateau at 2,000 meters will be °C.
