Calculate the lattice energy of lithium chloride from the following data:
a.Ionization energy of Li(g): Li(g) → Li+(g) + 1e- IE1 = 520 kJ/mol
b.Electron affinity of Cl(g): Cl(g) + 1 e- → Cl-(g) EA = -349 kJ/mol
c.Enthalpy of formation of LiCl(s): Li(s) + 1/2 Cl2(g) → LiCl(s) ΔH°f = -409 kJ/mol
d.Enthalpy of sublimation of Li: Li(s) → Li(g) ΔHsub = 159 kJ/mol
e.Bond energy of Cl2(g): Cl2(g) → 2Cl(g) ΔHBE = 244 kJ/mol
