2Na (s) + Cl2(g) → 2NaCl(s)
1 mol Na produces 1 mol NaCl
Molar mass Na = 23 g/mol
Mol Na in 11.5 g = 11.5 g / 23 g / mol = 0.5 mol Na
This will produce 0.5 mol NaCl
Molar mas NaCl = 23 + 35.45 = 58.45 g/mol
Mass of 0.5 mol NaCl = 0.5 mol * 58.45 g/mol = 29.225 g at 100 % yield
If actual yield is 85 % , then:
Mass of NaCl produced = 85%/100 % * 29.225 g = 24.84 g NaCl .
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