The force F (in newtons) of a hydraulic cylinder in a press is proportional to the square of sec x, where x is the distance (in meters) that the cylinder is extended in its cycle. The domain of F is [0, pi/3], and F(0) = 500. Find the average force exerted by the press over the interval [0, pi/3]. Round your answer to the nearest whole number. A. 675 newtons B. 827 newtons C. 138 newtons D. 225 newtons E. 276 newtons
