When an object is thrown upward with an
initial velocity of 96 ft/sec from a height of
256 ft, its height h after t seconds is given
by the function below.
h(t)= - 16t² +96t+256
UR
D
256 ft-
h(t)=16t+961 +256
h(t)
What is the height of the object after 0 sec. 1 sec, 3 sec, 4 sec, and 6 sec?
The height of the object is ft.
(Type each value. in order. Use a comma to separate answers as needed.)
