If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, it's height in feet after t second is given by y=95t−16t^2. Find the average velocity for the time period beginning when t=2 and lasting
(i) 0.1seconds
(ii) 0.01 seconds
(iii) 0.001 seconds
Finally based on the above results, guess what the instantaneous velocity of the ball is when t=2.
