There is a ball that is being shot upward with an initial speed of 64 ft/s. Initial velocity is 64 ft per second. The model is equal to -16. T. Esquire Plus 60 40. The instantaneous velocity is found by the party. The bullet is equal to one. The instantaneous velocity will be the same as the DST. The 33 Plus 64 are intended to be different. It will be -30 to plus 64 if it is equal to one. 32 feet per second is what it is. You should be fit per second. 32 feet per second squared is equal to instantaneous acceleration A. D. which is written as VT 80. This is unchanging. Part B. When does the ball hit the ground? How fast the ball travels when it hits the ground? When does the ball hit the ground? Will the ball hit the ground? H. T. will be equal to zero. If you take 16 years government, some minus T Plus four will be equal to zero. Either zero or four seconds equal to zero. When it was being shot and equal to force again at the time of the visit had just come down. The ball will come down after four seconds. When the ball hits the ground, how fast is it traveling? They have to find out how long it was. The expression is -30 to plus 64 -32 into four plus 64. The negative sign shows that the velocity direction is downward, not upward, so the magnitude will be 64 ft per second. This is how fast it will hit the ground. Thank you.
