Jack wrote this solution to solve for x.
Which statement is true?
O-3 is an extraneous solution because it is negative.
6 is an extraneous solution because it creates a zero
in the denominator.
O There are no extraneous solutions.
Both-3 and 6 are extraneous solutions because
they create a 0 in the denominator.
x+3
9
x²-11x-30
1 x+3
9
x-5 x-6 (x-6xx-5)
*+3
x-6
x-x-6xx-5)=
x-6xx-5)(x-6xx-5)
x-6=(x+3xx-5)-9
x-6-²-5x+3x-15-9
9
0=²-3r-18
0=(x-6Xx+3)
x=68x=-3
(x-6xx-5)
Factor
Multiply by the LCD
Simplify
Sampaty
Combine like terms.
Zero Product Property
Solve for x
