Which statement explains why △ABC is congruent to △A′B′C′
?
A. You can map △ABC onto △A′B′C′
by translating it 2 units up and reflecting it across the y-axis, which is a sequence of rigid motions.
You can map , triangle A B C, onto , △ A ′ B ′ C ′ , by translating it 2 units up and reflecting it across the , y, -axis, which is a sequence of rigid motions.
B.You can map △ABC onto △A′B′C′
by translating it 6 units left and reflecting it over the x-axis, which is a sequence of rigid motions.
You can map , triangle A B C, onto , △ A ′ B ′ C ′ , by translating it 6 units left and reflecting it over the , x, -axis, which is a sequence of rigid motions.
C.You can map △ABC onto △A′B′C′
by reflecting it across the x-axis and then across the y-axis, which is a sequence of rigid motions.
You can map , triangle A B C, onto , △ A ′ B ′ C ′ , by reflecting it across the , x, -axis and then across the , y, -axis, which is a sequence of rigid motions.
D. You can map △ABC onto △A′B′C′
reflecting it across the line y = x and rotating it 90° counterclockwise about the origin, which is a sequence of rigid motions.
