I just need to see whether I'm correct or not.
If [tex]log_{3}\ x^{2}=4[/tex] and [tex]log_{2}\ y^{3}=6[/tex], and [tex]log_{b}\ x+log_{b}\ y=\frac{1}{2}[/tex], where x, y > 0, then the value of b is ____
I got b = 1296 but the answer key gave b = 6.
Who's correct?