10n31y
contestada

I just need to see whether I'm correct or not.

If [tex]log_{3}\ x^{2}=4[/tex] and [tex]log_{2}\ y^{3}=6[/tex], and [tex]log_{b}\ x+log_{b}\ y=\frac{1}{2}[/tex], where x, y > 0, then the value of b is ____

I got b = 1296 but the answer key gave b = 6.

Who's correct?

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