At 4 seconds an astronaut's speed is 7 m/s and her direction is 68.66 degrees above the horizontal axis. Relative to her initial position, the x and y values at 4 seconds are x = 10 meters and y = 12.8 meters.
The astronaut’s position as a function of time is r = 2.5t î + ((1.6t^2)/2) ĵ
At t = 4.00 s, the key to the lunar module comes loose. If the magnitude of the acceleration due to gravity is 1.67 m/s2, at what time does the key strike the lunar surface? (Measure the time from when the key is released...i.e. don't count the 4.00 s)
How far in the x-direction does the key land relative to where she started?
