Consider the function f(t) = [tex]\sqrt[3]{(-3t+8)^{2} }*t^{2}[/tex]
(a) Compute f′(t).
(b) Show that the critical points of f(t) are t = 0, t = 2 and
t = 8/3.
(c) Determine the absolute minimum and maximum value that f
attains on [−1, 2.5]. You can use a calculator to give a decimal approximation of the final answer as needed. You can also use a graphing tool
to check your answer by looking at the graph.
