The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age.
Ex: If the input is:
Lee 18
Lua 21
Mary Beth 19
Stu 33
-1
then the output is:
Lee 19
Lua 22
Mary 0
Stu 34
# Split input into 2 parts: name and age
parts = input().split()
name = parts[0]
while name != '-1':
# FIXME: The following line will throw ValueError exception.
# Insert try/except blocks to catch the exception.
try:
age = int (parts [ 1 ]) + 1
print('{ }{ }'.format(name, age))
# Get next line
parts = input().split()
name = parts[0]
except ValueError:
print ('Invalid value!')
# Get next line
parts = input().split()
name = parts[0]
